-3x^2+70x-5=0

Solution for -3x^2+70x-5=0 equation:

-3x^2+70x-5=0

a = -3; b = 70; c = -5;
Δ = b2-4ac
Δ = 702-4·(-3)·(-5)
Δ = 4840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4840}=\sqrt{484*10}=\sqrt{484}*\sqrt{10}=22\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-22\sqrt{10}}{2*-3}=\frac{-70-22\sqrt{10}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+22\sqrt{10}}{2*-3}=\frac{-70+22\sqrt{10}}{-6}
$